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Which equation shows y=3x−1/5 in standard form? 5x−15y=1 15x−5y=1 5x−15y=−1 15x+5y=−1

Which equation shows y=3x−1/5 in standard form? 5x−15y=1 15x−5y=1 5x−15y=−1 15x+5y=−1
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1 vote
Which equation shows y=3x−1/5 in standard form?

5x−15y=1

15x−5y=1

5x−15y=−1

15x+5y=−1

asked
User Nielsen Ramon
by
7.2k points

1 Answer

3 votes

Answer:

The answer is 15x-5y=1

answered
User Clementine
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