What is \sqrt-16 + \sqrt49 written as a complex number in the form a + bi? A. 7 - 4i B. 4 + 7i C. 7 + 4i D. -4 + 7i

Question

What is
`\sqrt-16 + \sqrt49` written as a complex number in the form
`a + bi`?

A. 7 - 4i
B. 4 + 7i
C. 7 + 4i
D. -4 + 7i

Answer 1

7+4i

Explanation:

Answer 2

Answer: C. 7+4i

Explanation:

Just did the math.... square root of -16= 4i+ equate root of 49=7.

So...the answer is 7+4i