Question

PLEASE HELP

Write the full electronic configuration and draw the orbital box diagram of iron in its oxidation state in K3 Fe(CN)6. Hence determine the number of unpaired electrons in this state.

Answer 1

F
`e^(3t)`:1
`s^(2)`
`2s^2`2
`p^(6)`3
`s^(2)`3
`p^(6)`3
`d^(5)`

3d: The orbital diagram of iron is 5 boxes with an up arrow inside

The number of unpaired electrons in this state is 5.