Can someone show their work on how to do this: Calculate the number of moles of Al2O3 present in 23.87g. (Molar mass of Al2O3= 102.0g/mol)

Question

asked Dec 27, 2021 56.2k views

1 Answer

Shiami · Answer 1 · 2021-12-31T23:30:08+0000

Answer:

0.234 moles

Step-by-step explanation:

moles of Al2O3 = mass / molar mass

moles of Al2O3 = 23.87g / 102.0g/mol

moles of Al2O3 = 0.234 moles (to three significant figures)