Slopes of parallel \perpendicular lines

Question

asked Mar 2, 2023 180k views

1 Answer

Boris Burkov · Answer 1 · 2023-03-06T06:12:47+0000

Hello, the answer should be
m=(6)/(5)= 1,2 .

First, let's edit the given function as
parameter leave alone.

$15x+18y=270\\\\18y=270-15x\\\\y=(270-15x)/(18)\\ \\y=(270)/(18)-(15x)/(18)$

If the given equation looks like;

$y=f(x)\\\\y=ax+b$

then, the slope of the equation is the coefficient of
parameter (
)

The slope(m);

m=(-15)/(18)=(-5)/(6)

The product of the slopes of two perpendicular lines must be
. By that way, the slope of a line perpendicular to the given line is below:

$m_(expected)=(-1)/(m_(given)) \\\\m_(expected)=(-1)/((-5)/(6) )=(6)/(5)$

Good luck. If you have any questions, then feel free to ask in comments!