Answer:
 3°C
Step-by-step explanation:
Given parameters: 
Heat capacity = 300cal 
Specific heat capacity = 0.5cal/g°C
Mass of the object = 200g 
Initial temperature = 0°C 
Unknown: 
Final temperature = ? 
Solution: 
The heat capacity is the amount of heat required to raise the temperature of a substance by 1°C; 
 Mathematically ;
 H = m c x (t₂ - t₁)
H is the heat capacity 
m is the mass 
c is the specific heat capacity 
t is the temperature
 Insert the parameters and solve; 
 300 = 200 x 0.5 x (t₂- 0 )
 100 t₂ = 300 
 t₂ = 3°C