Question

Using the properties of real numbers ,prove that a<b and c<d= a+c<b+d​

Answer 1

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Answer 2

9514 1404 393

Step-by-step explanation:

a < b . . . . . given

0 < b -a . . . . . addition property of inequality

c < d . . . . . given

0 < d - c . . . . . addition property of inequality

0 < (b -a) +(d -c) . . . . addition is closed for positive real numbers

a +c < b +d . . . . . addition property of inequality