Question

Sove 3logx + 5 is equal to 8​

Answer 1

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`3 log(x) + 5 = 8`

Subtract sides 5

`3 log(x) + 5 - 5 = 8 - 5`

`3 log(x) = 3`

Divide sides by 3

`(3 log(x) )/(3) = (3)/( 3) \\`

`log(x) = 1`

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Reminder :

`log_(a)(x) = b`

`x = {a}^(b)`

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Thus ;

`log_(10)(x) = 1`

`x = {10}^(1)`

`x = 10`

Done...

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