Question

sodium hydroxide reacts with excess hydrochloric acid. calculate the mass of sodium hydroxide required to produce 117g of sodium chloride

Answer 1

NaoH+HcI→ NaCl +H2O

Na0H=23+16+l= 40 9m

Nacl=23 +35.5 =58.5 gm

mass of NaOH required=117x40/ 58.5 =80 gm

Answer 2

Molar mass of NaOH = 23+16+1 =40g/mol

Molar mass of NaCl = 23+35.5 =58.5g/mol

To produce 58.5g NaCl 40g NaOH is required

So, to produce 117g NaCl {(40/58.5)×117}g = 80g NaOH is required.

Hope, this helps.