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2H2S + 3O2 → 2SO2 + 2H2O 1. For every 10.0 g of H2S how many moles of SO2 are formed?
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2H2S + 3O2 → 2SO2 + 2H2O 1. For every 10.0 g of H2S how many moles of SO2 are formed?
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Apr 14, 2021
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2H2S + 3O2 → 2SO2 + 2H2O
1. For every 10.0 g of H2S how many moles of SO2 are formed?
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Nicola Ferraro
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Answer:10
Step-by-step explanation:
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Consider the balanced equation below. 2H2S + 3O2 ---> 2SO2 + 2H2O Which option gives the correct mole ratios? H2S:SO2 = 2:2 and O2:H2O = 3:2 H2S:SO2 = 2:3 and O2:H2O = 3:2 H2S:SO2 = 4:4 and O2:H2O = 5:4
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Use the given data at 500 K to calculate ΔG°for the reaction 2H2S(g) + 3O2(g) → 2H2O(g) + 2SO2(g) Substance H2S(g) O2(g) H2O(g) SO2(g) ΔH°f(kJ/mol) -21 0 -242 -296.8 S°(J/K·mol) 206 205 189 248
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2H2S + 3O2 2SO2 + 2H2O Which option gives the correct mole ratios? H2S:SO2 = 2:2 and O2:H2O = 3:2 H2S:SO2 = 2:3 and O2:H2O = 3:2 H2S:SO2 = 4:4 and O2:H2O = 5:4 H2S:SO2 = 4:6 and O2:H2O = 4:4
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