Question

write an equation for a prabola with a vertex at the origin, passing through(5,6), and symmetric with respect to the x-axis

Answer 1

a parabola with symmetry or mirror image across the x-axis, will be a horizontal parabola, namely one that opens either to the right or left.

a horizontal parabola will be a parabola whose independent variable is the "y", so it'll be an x(y) type of equation.

`~~~~~~\textit{horizontal parabola vertex form} \\\\ x=a(y- k)^2+ h\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{`