Question

Lead(II) chromate, PbCrO4, is a yellow paint pigment (called chrome yellow) prepared by a precipitation reaction. In a preparation, 52.5 g of lead(II) chromate is obtained as a precipitate. How many moles of PbCrO4 is this

Answer 1

n = 0.1624 moles

Step-by-step explanation:

`n=(m)/(M) \\n=(52.5)/(323.1937) \\n= 0.1624 mol`