asked 178k views
3 votes
The temperature of a sample of gas in a steel tank at 0.30 ATM at 25 Celsius if the pressure W20.59 ATM what would be the final temperature inside the tank in kelvin

1 Answer

4 votes

The final temperature : 313.06 °C

Further explanation

Gay Lussac's Law

When the volume is not changed, the gas pressure is proportional to its absolute temperature


(P_1)/(T_1)=(P_2)/(T_2)

P1=0.3 atm

T1=25 + 273=298 K

P2=0.59 atm


\tt (0.3)/(298)=(0.59)/(T_2)\\\\T_2=586.06=313.06~^oC

answered
User Mohinder Singh
by
8.4k points
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