Question

The diagram shows the top view of a 65-kg student at point A on an amusement park ride. The ride spins the student in a horizontal circle with a radius of 2.5 m, at a constant speed of 8.6 m/s. The floor is lowered and the student remains against the wall without falling to the floor.

The magnitude of the centripetal force acting on the student at point A is approximately
Question 1 options:

A.) 1923 N
B.) 47 N
C.) 1398 N
D.) 223 N

Answer 1

A.) 1923 N

Step-by-step explanation:

Given parameters:

Mass of the student = 65kg

Radius = 2.5m

Velocity = 8.6m/s

Unknown:

Centripetal force = ?

Solution:

Centripetal force is a force that keeps a body moving along a circular path.

It is mathematically expressed as;

F =
`(mv^(2) )/(r)`

m is the mass

v is the velocity

r is the radius

Insert the parameters and solve;

F =
`(65 x 8.6^(2) )/(2.5)` = 1923N