Question

John is diving off a springboard which is 10 meters above the water. He weighs 75 kg. Based on this information, how fast will John be moving when he hits the water below?

Answer 1

v = 14 m /s

Step-by-step explanation:

vertical displacement h = 10 m

acceleration = g = 9.8 m /s²

initial vertical velocity u = 0

v² = u² + 2 g h

= 0 + 2 x 9.8 x 10

v = 14 m /s