Question

If a boat and its riders have a mass of 1100 kg and the boat drifts in at 1.6 m/s how much work does Sam do to stop it

Answer 1

-1408 J

Step-by-step explanation:

W= Kf-Ki

Kf= 0 because boat stopped so no velocity

Ki= 1/2 mv^2

Ki= 1/2 (1110)(1.6)^2

Ki= 1408

W= Kf-Ki

W= 0- 1408 = -1408 J

Answer 2

1408 J.

Step-by-step explanation:

From the question given above, the following data were obtained:

Combined mass (m) = 1100 kg

Velocity (v) = 1.6 m/s

Workdone =?

Next, we shall determine the kinetic energy of boat. This can be obtained as follow:

Combined mass (m) = 1100 kg

Velocity (v) = 1.6 m/s

Kinetic energy (K.E) =?

K.E = ½mv²

K.E = ½ × 1100 × 1.6²

K.E = 550 × 2.56

K.E = 1408 J

Thus the kinetic energy of the boat is 1408 J.

Since the boat is moving with a kinetic energy of 1408 J, it will take an equivalent amount of energy to stop the boat. Hence, the Workdone to stop the boat is 1408 J.