Question

1.
1. The factors of 64a3 + 343b3 are​

Answer 1

(4a + 7b)(16a² - 28ab + 49b²)

Explanation:

Use the sum of two cubes to factor

In addition

a³ + b³ = (a + b)(a² - ab + b²)

In subtraction

a³ - b³ = (a - b)(a² + ab + b²)

64a³ + 343b³ = (4a + 7b)(16a² - 28ab + 49b²)