The second of three numbers is 11 less than the first. The third number is 5 less than the second. If the first number is twice as large as the third, find the three numbers.

Question

asked Jun 15, 2021 274 views

1 Answer

Robie Basak · Answer 1 · 2021-06-21T13:56:12+0000

Answer:The sum of three numbers is 112.

a+b+c=112

The second number is 5 times the first.

b=5a

so a+5a+c=112

6a+c=112

The third number is 20 less than the second. What is the second number?

c=5a-20

6a+5a-20=112

11a-20+20=112+20

11a/11=132/11

a=12

Explanation: