Question

At 2:00 PM a car's speedometer reads 30 mi/h. At 2:20 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:20 the acceleration is exactly 60 mi/h2.

Answer 1

The correct answer will be "60 min/hour".

Explanation:

At time 2:00 PM

A car reads = 30 mi/h

At time 2:20 PM

A car reads = 50 mi/h

Now,

At time 2:00 PM

t = 0

At time 2:20 PM

t =
`(1)/(3)`

`v(0)=30`

`v((1)/(3))=50`

For MVT,

`v'(c)=(v((1)/(3) -v(0)))/(((1)/(3) ))`

`=(20)/((1)/(3) )`

`=60 \ min/hour`