Question

A chemist requires 0.802 mol Na2CO3 for a reaction. How many grams does this correspond to?

Answer 1

Ok:

Step-by-step explanation:

So grams = mols*MolarMass. Here, MolarMass (MM) = 105.99g which can be found using the periodic table. mols is given to be 0.802. We can then plug in to get that it corresponds to 85.0g.