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Vertex form of f(x)=x^2-6x-40

Vertex form of f(x)=x^2-6x-40
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Vertex form of f(x)=x^2-6x-40

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User Mike Delta
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7.8k points

1 Answer

4 votes

Answer:

f(x)=(x-10)(x+4)

Explanation:

Vertex form of f(x)=x^2-6x-40-example-1
answered
User MasterJoe
by
7.9k points
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