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Vertex Form of f(x)=x^2-6x-40

Vertex Form of f(x)=x^2-6x-40
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1 vote
Vertex Form of f(x)=x^2-6x-40

asked
User Sethmr
by
9.3k points

1 Answer

3 votes
The vertex form is
y = (x+3)^2−49
answered
User WayneSan
by
8.4k points
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