Question

Parent 1 has brown fur. Brown is a dominant color. Parent 1 genotype is Bb. Parent 2 has yellow fur. Yellow is a recessive color. Parent 2 genotype is bb. What is the probability that an offspring has two dominant alleles? Create a Punnett square to help you.

Answer 1

0

Step-by-step explanation:

In this cross, brown fur (B) is dominant to yellow fur (b).

Parent 1 has brown fur, and a genotype Bb. Parent 2 has yellow fur, and a genotype bb.

The cross is Bb x bb

B b

b Bb bb

b Bb bb

50% of the offspring are heterozygous, and have brown fur (Bb). 50% of the offspring are h0m0zygous for the recessive allele (bb). However, it is not possible for the offspring to have two dominant alleles (BB) from this cross, so the probability is 0.