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7 votes
How to solve 2x^2+5-12=0 by factoring with detail, please!!!!!!

asked
User VSN
by
8.6k points

1 Answer

12 votes

Answer:


x = \frac 32, ~ x = -4

Step by step explanation:


~~~~~~~2x^2+5x-12=0\\\\\implies 2x^2 +8x-3x-12=0\\\\\implies 2x(x+4) -3(x+4) = 0\\\\\implies (2x-3)(x+4) = 0\\\\\implies 2x -3 = 0~~~~ \text{or}~~~~~~~~ x +4 = 0\\\\\implies 2x = 3~~~~~~~~~ \text{or}~~~~~~~~x = - 4\\\\\implies x = \frac 32~~~~~~~~~~ \text{or}~~~~~~~~x = - 4\\\\\text{Hence,}~ x = \frac 32, ~ x = -4

answered
User Ersefuril
by
8.2k points

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