Question

7. In the lectures an example was given of how the Fermi levels were filled. There were 20 electrons with a total energy of 106 eV. The states were 1 eV apart, starting at 1/2 eV. Pauli exclusion limits the number of electrons per level to 2. a. Find the 24 allowed distributions. b. What is the average occupancy of each energy state

Answer 1

F(e) =
`(1)/(1 + e^((e-ef)/kt) )`

Step-by-step explanation:

A) Determine the 24 allowed distributions

attached below

B ) The average occupancy of each energy state

F(e) =
`(1)/(1 + e^((e-ef)/kt) )`

for the best fit/condition to determine the average occupancy of each energy state

Ef ( fermi energy ) = 9.998 eV

Kt = 1.447 eV

T = 16800 k