Question

Read the scenario, then answer the questions.

A 2 kg ball is thrown upward with a velocity of 15 m/s.

What is the kinetic energy of the ball as it is being thrown?


What is the potential energy of the ball when it gets to its maximum height just before falling back to the ground?

Answer 1

`KE=15J`

Step-by-step explanation:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. So,
`KE=(1)/(2)mv^(2)`, which means our equation is:

`KE=(1)/(2)(2kg)15m/s^(2)`

`KE=(1kg)15m/s^2`

`KE=15J`

Answer 2

Ke=225 Pe=225

Step-by-step explanation:

Did it on edg 2020 :3