Question

A parachute on a racing dragster opens and changes the speed of the car from 79.33 m/sec to 41.55 m/sec in a period of 5.21 seconds. What is the acceleration of the dragster?

Answer 1

c: -7.25

Step-by-step explanation:

Here we can use the equation v=u+at

Where v is the final velocity

u is the initial velocity

a is acceleration

and t is time

41.55=79.33+a(5.21)

41.55-79.33=5.21a

-37.78=5.21a

a=-7.25 m/
`s^2`

The negative sign is due to the fact that they are slowing down