Question

Multiply
[(x-1)/(x^2-2x-3)].[(3x-9)/(x+2)]

Answer 1

3(x -1) / (x + 1)(x + 2).

Explanation:

(x-1)/(x^2-2x-3)].[(3x-9)/(x+2)

Factoring the denominator and 3x - 9:

= (x - 1) / (x + 1)(x - 3) * 3(x - 3) / (x + 2)

The (x - 3)'s cancel out, so we have:

(x - 1)/(x + 1) * 3 / (x + 2)

= 3(x -1) / (x + 1)(x + 2).