Question

F △HLI ~ △JLK by the SSS similarity theorem, then StartFraction H L Over J L EndFraction = StartFraction I L Over K L EndFraction is also equal to which ratio?

Answer 1

a

Explanation:

got it right

Answer 2

`(HI)/(Jk)`

Explanation:

Recall that, when two triangles are said to be similar to each other, it means that their corresponding side lengths are proportional and the ratio of their side lengths are equal.

We are given that ∆HLI ~ ∆JLK which is justified by the SSS similarity theorem, therefore,
`(HL)/(JL) = (IL)/(KL)`. This ratio will also be equal to the ratio of the corresponding lengths of their third side, that is:

`(HI)/(Jk)`

(See attachment where both ∆s have been drawn for better understanding).