Question

A computer randomly puts a point inside the rectangle. What is the probability

that the point does not land in triangle T?

Answer 1

Just took test its 7/8

Explanation:

Answer 2

87.5%

Step-by-step explanation:

The area of the entire rectangle is 8 by 6,

8x6=48 so the area is 48 units^2.

The area of the triangle is A=1/2bh

A=1/2(2)(6)

A=1(6)

A=6 units^2

6/48=0.125

0.125=12.5%

You need to find the percent it will not land in the triangle, so subtract 12.5 from 100.

100-12.5=87.5

There is an 87.5% chance it will not land in the triangle