Question

Calculate the peak voltage (in Volts) of a generator that rotates its 200-turn, 0.100 m diameter coil at 3.5 x 103 rpm in a 0.7 T field. You should round your answer to the nearest integer, do not include unit.

Answer 1

Angular velocity of the coil :

`\omega=(2\pi n)/(60)`

`\omega=(2* \pi* 3500)/(60)\\\\\omega =366.52\ rad/s`

Now,

Peak voltage is given by :

`V=NAB\omega\\\\V= 200* (\pi (0.1)^2)/(4)* 0.7* 366.52\\\\V=403.01\ V`

Hence, this is the required solution.