Question

1. A balloon drifts 100 m towards the west in 10 seconds, then the wind suddenly changes

and the balloon flies 60m towards the east in the next 6 seconds.


a) What total distance did it travel? 160 meters


b) What was the average speed during the first 10 seconds?


c) What was its average speed during the next 6 seconds?



d) What was its average speed for the entire trip?


e) What was its total displacement?


1) What was its average velocity during the first 10 seconds?


g) What was its average velocity during the next 6 seconds?


h) What was its average velocity for the entire trip?

Answer 1

Step-by-step explanation:

a) The total distance traveled by the balloon = (100 + 60) m

= 160 metes

b) speed =
`(distance covered)/(time taken)`

The average speed for the first flight =
`(100)/(10)`

= 10 m/s

c) The speed during its next flight =
`(60)/(6)`

= 10 m/s

d) Average speed for the entire trip =
`((10 + 10))/(2)`

= 10 m/s

e) Total displacement =
`\sqrt{(100)^(2) + (60)^(2) }`

=
`√(13600)`

= 116.62 m

f) velocity =
`(displacement)/(time)`

Average velocity during the first 10 seconds =
`(100)/(10)`

= 10 m/s

g) Average velocity during the next 6 seconds =
`(60)/(6)`

= 10 m/s

h) Average velocity for the entire trip =
`\sqrt{(10)^(2) + (10)^(2) }`

=
`√(200)`

= 14.14 m/s