Question

What is the y-intercept of the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the

point (15,-5)?
O y=x-20
O y=-3x+20
0 v= 2 X-20
O y=-3x+20

Answer 1

Answer: y=-5/3x+20 or y=-1 2/3x+20, so 20.

Step-by-step explanation: Actually, neither one of those options are correct. You may recall that the slope of the perpendicular line would be the exact opposite, the reciprocal, of the given line. The exact opposite of 3/5x is -5/3x, which could be reduced to -1.5x. From there, you could substitute x and y, which are 15 and -5 in this case, into the y=mx+b equation:

-5=-5/3(15)+b *b is y-intercept*

-5=-25+b Multiplied -5/3 by 15 first

-20=b Subtracted -25 from both sides (it'd be --25, so

basically just +25)

20=b Reciprocate b because you need the opposite

Hope this helps,

Lacia :))