Question

Can somebody help me with this? Please and Thank you

Answer 1

`\text{Given that,}~ p(x) = x^2 +3 ~ \text{and}~ h(x) = √(x-3) \\\\(p \circ h)(x)\\\\=p(h(x))\\\\=p\left(√(x-3)\right)\\\\=\left(√(x-3) \right)^2 +3\\\\=x-3 +3\\\\=x`