Question

One method for removing hydrogen sulfide impurities from natural gas is by its reaction with oxygen at high temperatures to form sulfur and water vapor. After balancing the following equation, determine the coefficient in front of the reactant O2. H2S(g) + O2(g) → S8(l) + H2O(g) Group of answer choices

Answer 1

The coefficient in front of the reactant O₂ in the balanced equation H₂S(g) + O₂(g) → S₈(l) + H₂O(g) is 8.

Step-by-step explanation:

To balance the chemical equation H₂S(g) + O₂(g) → S₈(l) + H₂O(g), we need to ensure that the number of atoms of each element is the same on both sides of the equation. The coefficient in front of O2(g) is 8, as it balances the number of sulfur atoms on the product side of the equation. Therefore, the balanced equation is 2H₂S(g) + 8O₂(g) → S8(l) + 8H₂O(g).

Answer 2

4

Step-by-step explanation:

H2S(g) + O2(g) → S8(l) + H2O(g)

Upon balancing the equation;

8H2S(g) + 4O2(g) → S8(l) + 8H2O(g)

The coefficient of O2 in the reaction above is 4.