Question

calculate the freezing point of a solution of 30 g methyl salicylate c7h6o2 dissolved in 800 g of benzene

Answer 1

Answer: The freezing point of the solution will be
`4.3^0C`

Step-by-step explanation:

Depression in freezing point is given by:

`\Delta T_f=i* K_f* m`

`\Delta T_f=T_f^0-T_f=(5.5-T_f)^0C` = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

`K_f` = freezing point constant =
`4.90^0C/m`

m= molality

`\Delta T_f=i* K_f* \frac{\text{mass of solute}}{\text{molar mass of solute}* \text{weight of solvent in kg}}`

Weight of solvent (benzene)= 800 g = 0.8 kg

Molar mass of solute ( methyl salicylate) = 152.1 g/mol

Mass of solute ( methyl salicylate) = 30 g

`(5.5-T_f)^0=1* 4.90^0C/m* (30g)/(152.1 g/mol* 0.8kg)`

`(5.5-T_f)0C=1.2`

`T_f=4.3^0`

The freezing point of the solution will be
`4.3^0C`