Question

At the city museum, child admission is $6.00 and adult admission is $9.60. On Tuesday, 177 tickets were sold for a total sales of $1350.00. How many adult

tickets were sold that day?

Answer 1

80 adult tickets were sold that day.

This is a two equation problem.

First, let:

a = adult tickets

c = child tickets

`6c + 9.6a = 1350`

`c + a = 177`

Now, solve for either variable (c or a). We're going to isolate "c" in the second equation and plug it into the first.

`c + a = 177`

`c = 177 - a`

Plug it in:

`6(177 - a) + 9.6a = 1350`

`1062 - 6a + 9.6a = 1350`

`1062 + 3.6a = 1350`

`3.6a = 288`

`a = 80`

Now, plug in 80 for "a" in either of the equations to find "c."

`c + (80) = 177`

`c = 97`

Rather than solving algebraically, as shown above, you can also graph the two equations, and wherever they intersect will be the solution.