Question

A gas occupies 1.00 L at 273 K. What is the volume at 606 °C?

Answer 1

3.22 L

Step-by-step explanation:

0.00 C = 273 K

k = C +273

606 K + 273 K = 879 K

879/273 = 3.219

V2 = 3.22 L