Answer:
Perhaps this will help. We have 11 identical candies, that we wish to distribute between 3 children C1. C2, and C3. (Possibly one or more of the children will get no candies.) For every solution of x1+x2+x3=11, we have a way of distributing the candies, x1 to C1, x2 to C2, and X3 to C3. conversely, every distribution of candies gives us a solution to x1+x2+x3=11.
Explanation:
Can u please answer my recent question!!!!