Question

A 75.0 kg skier slides down a 75.0 m high slope without friction. The velocity of the skier at the bottom of the slope is

Answer 1

v = 38.34 m

Step-by-step explanation:

Given that,

Mass of a skier, m = 75 kg

It falls down a 75.0 m high slope without friction, h = 75 m

We need to find the velocity of the skier at the bottom of the slope. It is based on the concept of conservation of energy. So, v is the required velocity. So,

`mgh=(1)/(2)mv^2\\\\v=√(2gh) \\\\v=√(2* 9.8* 75) \\\\v=38.34\ m/s`

So, the velocity of the skier at the bottom of the slope is 38.34 m.