Question

What is the slope of a line perpendicular to the line whose equation is 9x+3y=-27

Answer 1

y = (1/3)x - 27 <-- perpendicular line

Explanation:

9x + 3y = (-27)

3x + y = (-27)

y = (-3x) - 27 <-- original line

y = (-3x) - 27 <-- original line

slope = (-3)

slope = (-3/1)

inverse = (1/-3)

negative inverse = (1/3)

y = (1/3)x - 27 <-- perpendicular line