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Solve the system of equations: y = 2x – 3 y = x2 – 3 A. (0, –3) and (2, 1) B. (0, 3) and (2, 0) C. (–1, –5) and (4, 5) D. (3, 6) and (–3, 6)

Solve the system of equations: y = 2x – 3 y = x2 – 3 A. (0, –3) and (2, 1) B. (0, 3) and (2, 0) C. (–1, –5) and (4, 5) D. (3, 6) and (–3, 6)
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Solve the system of equations: y = 2x – 3 y = x2 – 3 A. (0, –3) and (2, 1) B. (0, 3) and (2, 0) C. (–1, –5) and (4, 5) D. (3, 6) and (–3, 6)

asked
User Martyn Lovell
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7.9k points

1 Answer

13 votes

Answer:

A. (0,-3) the other possible anser is (2,1) but that's not an option

answered
User ForX
by
7.9k points
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