Question

You are an employee at "cash for gold" and a customer comes in looking to exchange gold for money. They claim to have 3.47 gram nugget of fold. How many particles (atoms) of gold are in one nugget? With work shown

Answer 1

The number of atoms in 3.47 gram nugget of gold is approximately 1.0606 × 10²² atoms

Step-by-step explanation:

The given mass of gold = 3.47 grams

The molar mass of gold = 196.96657 g/mol

The number of moles of gold in 3.47 grams of gold = 3.47 grams/(196.96657 g/mol)

The number of moles of gold in 3.47 gram nugget of gold = 0.01762 moles

The number of atoms in one mole of gold = 6.02 × 10²³ atoms

The number of atoms in 0.01762 moles of gold = 6.02 × 10²³ atoms/mole × 0.01762 moles

The number of atoms in 0.01762 moles of gold ≈ 1.0606 × 10²² atoms

∴ The number of atoms in 3.47 gram nugget of gold ≈ 1.0606 × 10²² atoms.