Question

Find a so that the point (-1,3) is on the graph of f(x) = ax^2 + 2

Answer 1

a = 1

Explanation:

Plug in the point into the equation, then solve for a:

f(x) = ax² + 2

3 = a(-1²) + 2

3 = a + 2

1 = a

So, a = 1