Question

If 18.2 of 0.800 solution are needed to neutralize 5.00 of a household ammonia solution, what is the molar concentration of the ammonia

Answer 1

2.91M is the concentration of the household ammonia solution

Step-by-step explanation:

18.2mL of a 0.800M HCl solution to neutralize 5.00mL

The reaction of HCl with NH3 is:

HCl + NH3 → NH4Cl

Thus, the moles of HCl needed to neutralize the household are equal to moles of NH3. That is:

18.2mL = 0.0182L * (0.800mol / L) = 0.01456 moles HCl = Moles NH3.

In 5.00mL = 0.005L:

0.01456 moles NH3 / 0.005L =

2.91M is the concentration of the household ammonia solution