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Y=-x^3 + 2x2 - 4 at (0, -4)
Find the normal line

1 Answer

4 votes

Answer:

True

Explanation:

I will assume you want to see if (0, -4) is a point on the line.

y = -x³ + 2x² - 4

~Substitute

-4 = -(0)³ + 2(0)² - 4

~Simplify

-4 = -4

Best of Luck!

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User AKG
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