Question

How many solutions exist for each system of equations?
x + 2y = –1
2x + 3y = 0

Answer 1

2 solutions x = 3 y = -2.

Explanation:

x + 2y = –1

2x + 3y = 0

Multiply first equation by -2:

-2x - 4y = 2 Adding this to second equation:

- y = 2

y = -2.

Plug this into first equation:

x - 4 = -1

x = 3.