Question

Consider a surface at a uniform temperature of 1000 K. Determine the maximum rate of thermal radiation that can be emitted by this surface, in W/m2.

Answer 1

The value is
`E_b_(max) = 56.700 *10^(3) \ W/m^2`

Step-by-step explanation:

From the question we are told that

The uniform temperature is
`T = 1000 \ K`

Gnerally the rate of thermal radiation is mathematically represented as

`E_b = \epsilon * \sigma* T^4`

Generally
`\epsilon` is the emissivity and at maximum the value is 1

`\sigma` is the Stefan Boltzmann constant with value
`\sigma = 5.67 *10^(-8) \ W/m^2 \cdot K^4`

So

`E_b_(max) = 1 * 5.67 *10^(-8)* 1000^4`

=>
`E_b_(max) = 56.700 *10^(3) \ W/m^2`