Question

How do I solve this?
50e^(0.035x)=200

Answer 1

x ≈ 39.608

Explanation:

Using the rule of logarithms

log
`x^(n)` = nlogx and lne = 1

Given

50
`e^(0.035x)` = 200 ( divide both sides by 50 )

`e^(0.035x)` = 4 ( take the ln of both sides )

ln
`e^(0.035x)` = ln4 , that is

0.035xlne = ln4

0.035x = ln4 ( divide both sides by 0.035 )

x =
`(ln4)/(0.035)` ≈ 39.608 ( to 3 dec. places )