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asked Jul 3, 2021 172k views

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The solution for x^2+2x+8<0_ is

Mathematics
college

Andrew Wynham asked

by Andrew Wynham

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Answer:

Explanation:

−2x−8=0

−4x+2x−8=0

x(x−4)+2(x−4)=0

(x+2)(x−4)=0

⟹x=−2,4

Eric Speelman answered Jul 8, 2021

by Eric Speelman

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The solution for x^2+2x+8<0_ is

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